Exercise | Wiskunde op Tilburg University

Determine the derivative of

$y(x) = 37 \cdot 2^x$ .

Antwoord 1 correct

Correct

Antwoord 2 optie

$y'(x) = 37\cdot 2^x$ .

Antwoord 2 correct

Fout

Antwoord 3 optie

$y'(x) = 37x2^{x-1}$ .

Antwoord 3 correct

Fout

Antwoord 4 optie

$y'(x) = \ln(2)\cdot 2^x$ .

Antwoord 4 correct

Fout

Antwoord 1 optie

$y'(x) = 37\cdot \ln(2) 2^x$ .

Antwoord 1 feedback

Correct: We use the scalar product rule with

$c=37$ and

$u(x) = 2^x$ . In two steps we find

$\begin{align*} u'(x) &= 2^x \ln(2) = \ln(2)2^x,\\ y'(x) &= 37 \cdot \ln(2)2^x. \end{align*}$

Go on.

Antwoord 2 feedback

Wrong: You did use the scalar product rule, but the derivative of

Antwoord 3 feedback

Wrong: You did use the scalar product rule, but the derivative of

Antwoord 4 feedback

Wrong: You have to use the scalar product rule.

See Derivatives of elementary functions.