Consider the function f(x,y)=2x+ln(y−1)−13. Determine the function value if the first input variable (x) has a value of 3 and the second input variable a value of 2.
Antwoord 1 correct
Correct
Antwoord 2 optie
ln(2)−9.
Antwoord 2 correct
Fout
Antwoord 3 optie
(2,3).
Antwoord 3 correct
Fout
Antwoord 4 optie
The values of the input variables are outside the domain of the function f(x,y).
Antwoord 4 correct
Fout
Antwoord 1 optie
−5.
Antwoord 1 feedback
Correct: f(3,2)=23+ln(2−1)−13=8+0−13=−5.
Go on.
Go on.
Antwoord 2 feedback
Wrong: You have to determine f(3,2), not f(2,3).
Try again.
Try again.
Antwoord 3 feedback
Wrong: The function value is not equal to the value of the input variables.
See Functions of two variables.
See Functions of two variables.
Antwoord 4 feedback
Wrong: The domain consists of all the feasible combinations of x and y. x may take any value, while y should be striclty greater than 1. Since x=3 and y=2, there is no problem with the domain.
Try again.
Try again.