Example | Wiskunde op Tilburg University

We determine the stationary points of the function

$y(x)=x^2+5x+7$ .

$y'(x)=2x+5$ . Hence,

$y'(x)=0$ if

$x=-2\frac{1}{2}$ .

Consequently, the only stationary point is

$x=-2\frac{1}{2}$ .