Exercise | Wiskunde op Tilburg University

The function

$z(x,y)=x^2+y^2$ has exactly one minimum. Determine that minimum.

Antwoord 1 correct

Correct

Antwoord 2 optie

$(x,y)=(0,0)$ .

Antwoord 2 correct

Fout

Antwoord 3 optie

$z(-1,-1)=-2$ .

Antwoord 3 correct

Fout

Antwoord 4 optie

$(x,y)=(-1,1)$ .

Antwoord 4 correct

Fout

Antwoord 1 optie

$z(0,0)=0$ .

Antwoord 1 feedback

Correct:

$z(0,0)=0$ and

$z(x,y)\geq 0$ for every other combination of

$x$ and

$y$ . Hence,

$z(0,0)=0$ is the minimum of the function.

Go on.

Antwoord 2 feedback

Wrong: Note the difference between a minimum and a minimum location.

See Minimum/maximum.

Antwoord 3 feedback

Wrong:

$(-1)^2\neq -1$ .

Try again.

Antwoord 4 feedback

Wrong: Note the difference between a minimum and a minimum location.

See Minimum/maximum.