Exercise 1 | Wiskunde op Tilburg University

Determine

$p$ and

$q$ such that

$p=^2\!\log 2^5$ and

$q= 3^{^3\!\log 6}$ .

$p=25$ ,

$q=216$

$p=10$ ,

$q=18$

$p=5$ ,

$q=6$

$p=32$ ,

$q=729$

Determine

$p$ and

$q$ such that

$p=^2\!\log 2^5$ and

$q= 3^{^3\!\log 6}$ .

Antwoord 1 correct

Correct

Antwoord 2 optie

$p=32$ ,

$q=729$

Antwoord 2 correct

Fout

Antwoord 3 optie

$p=25$ ,

$q=216$

Antwoord 3 correct

Fout

Antwoord 4 optie

$p=10$ ,

$q=18$

Antwoord 4 correct

Fout

Antwoord 1 optie

$p=5$ ,

$q=6$

Antwoord 1 feedback

Correct:

$^a\!\log a^y$
$x = a^{^a\!\log x}$

Go on.

Antwoord 2 feedback

Wrong:

$^2\!\log 2^5\neq 2^5$ .

See Relation logarithmic and exponential functions.

Antwoord 3 feedback

Wrong:

$^2\!\log 2^5\neq 5^2$ .

See Relation logarithmic and exponential functions.

Antwoord 4 feedback

Wrong:

$^2\!\log 2^5\neq 2 \cdot 5$ .

See Relation logarithmic and exponential functions.