Determine all stationary points of y(x)=x2+6x+7.
x=612
x=1 and x=7
x=3
y(x) has no stationary points.
Determine all stationary points of y(x)=x2+6x+7.
Antwoord 1 correct
Correct
Antwoord 2 optie
x=1 and x=7
Antwoord 2 correct
Fout
Antwoord 3 optie
x=612
Antwoord 3 correct
Fout
Antwoord 4 optie
y(x) has no stationary points.
Antwoord 4 correct
Fout
Antwoord 1 optie
x=3
Antwoord 1 feedback
Correct: y(x)=2x+6. Hence, y(x)=0 gives x=3. Therefore, x=3 is the unique stationary point of y(x).

Go on.
Antwoord 2 feedback
Wrong: A stationary point c is not a point such that y(c)=0.

See Stationary point.
Antwoord 3 feedback
Wrong: y(x)2x+6+7.

See Derivative.
Antwoord 4 feedback
Wrong: y(x) does have a stationary point.

See Example.