Earlier we saw that y(x)=e3x2−1 is a composite function that can be written as y(x)=u(v(x)), with v(x)=3x2−1 and u(v)=ev. By the use of the chain rule we can determine the derivative of this function:
v′(x)=3⋅2x=6xu′(v)=evy′(x)=u′(v(x))⋅v′(x)=ev(x)⋅6x=6xe3x2−1.
v′(x)=3⋅2x=6xu′(v)=evy′(x)=u′(v(x))⋅v′(x)=ev(x)⋅6x=6xe3x2−1.