Solve (x2−4)(x+1)≥−2(x+2).
−2≤x≤1
x≥−2
x≥1
−2≤x≤0 or x≥1
Correct:
(x2−4)(x+1)=−2x−4⇔x3+x2−4x−4=−2x−4⇔x3+x2−2x=0⇔x(x2+x−2)=0.
Hence, x=0 or x2+x−2=0. This Quadratic function gives x=1 or x=−2. Via a sign chart (See Example 2 (film)) we get −2≤x≤0 or x≥1.
Go on. $
Wrong: x=0 is also a solution of the corresponding equation.
Try again.
Wrong: x=0 is also a solution of the corresponding equation.
Try again.
Wrong: x=0 is also a solution of the corresponding equation.
Try again.