Determine the inverse of $y(x)=(x+1)^2$.
This inverse does not exist.
$x(y)=\sqrt{y}-1$
$x(y)=\sqrt{y} +1$
None of the other answers is correct.
Determine the inverse of $y(x)=(x+1)^2$.
Antwoord 1 correct
Correct
Antwoord 2 optie
$x(y)=\sqrt{y}-1$
Antwoord 2 correct
Fout
Antwoord 3 optie
$x(y)=\sqrt{y} +1$
Antwoord 3 correct
Fout
Antwoord 4 optie
None of the other answers is correct.
Antwoord 4 correct
Fout
Antwoord 1 optie
This inverse does not exist.
Antwoord 1 feedback
Correct: For every $y\geq 0$ the equation $y=(x+1)^2$ is met by both $x=\sqrt{y}-1$ and $x=-\sqrt{y}-1$. Hence, the equation $y=(x+1)^2$ has multiple solutions. Therefore, $y(x)$ has no inverse.

Go on.
Antwoord 2 feedback
Wrong: This is not the only solution of the equation.

Try again.
Antwoord 3 feedback
Wrong: Consider the minus-sign.

Try again.
Antwoord 4 feedback
Wrong: The correct answer is among them.

Try again.