Consider the function $f(x,y)=\min\{6x,8y\}$. Calculate the function value at $(x,y)=(2,1)$.
$1$.
$12$.
$4$.
$8$.
Correct:$f(2,1) = \min\{6\cdot2,8\cdot1\} = \min\{12,8\} = 8$.
Go on.
Wrong: The idea is not take the minimum of the two input variables.
See Minimum functions and the corresponding Extra explanation.
Wrong: 12 is not the minimum of the two elements between brackets.
See Minimum functions and the corresponding Extra explanation.
Wrong: $\min\{6\cdot2,8\cdot1\} \neq 6\cdot2-8\cdot1$.
See Minimum functions and the corresponding Extra explanation.