We determine x such that 2x82x+2=22x2+15(4x)2.

2x82x+2=22x2+15(4x)22x(23)2x+2=212x2+1542x2x26x+6=2x2+16(22)2x27x+6=2x2+1624x27x+6=2x24x+167x+6=x24x+16x211x+10=0(x10)(x1)=0x=1 or x=10.