• Minimize z(x,y)=3x+2y+4                      
  • Subject to x2y=48
  • Where x,y>0
z(4,3)=22
z(3438513,38513)=41438513+4
z(43336,336)=6336+4
None of the other answers is correct.
  • Minimize z(x,y)=3x+2y+4                      
  • Subject to x2y=48
  • Where x,y>0
Antwoord 1 correct
Correct
Antwoord 2 optie
z(43336,336)=6336+4
Antwoord 2 correct
Fout
Antwoord 3 optie
z(3438513,38513)=41438513+4
Antwoord 3 correct
Fout
Antwoord 4 optie
None of the other answers is correct.
Antwoord 4 correct
Fout
Antwoord 1 optie
z(4,3)=22
Antwoord 1 feedback
Correct: The First-order condition gives 32=2xyx2=2yx what results in x=43y. Plugging this into the restriction gives (43y)2y=48, which results in y=3 with x=4. z(4,3)=22. There are no boundaries. Therefore, we take (for instance) z(2,12)=34 and z(6,113)=2423. From this it follows that z(4,3)=22 is the minimum.

Go on.
Antwoord 2 feedback
Wrong: (43y)243y2.

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Antwoord 3 feedback
Wrong: 3x=4y does not result in x=34y.

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Antwoord 4 feedback
Wrong: The correct answer is among them.

Try again.