Determine all a such that the following equation has exactly two solutions: x5+a2x=2.
−√5
For all a.
For no a.
The correct answer is not among the other options.
Correct: Note that the equation is not defined for x=0. Hence, for no a is x=0 a solution.
If a=0: x5=2 has one solution.
For a≠0 we have x5+a2x=2.
Rewriting by multiplying by x gives 15x2−2x+a2=0.
D=4−45a2.
D=0 for a=−√5 or a=√5.
D>0 for −√5<a<√5.
Hence, two solutions for −√5<a<0 or 0<a<√5.
Go on.
Wrong: What is the equation for a=0?
Try again.
Wrong: Try again.
Wrong: Try again.